(y^2-4)(3/y-2)

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Solution for (y^2-4)(3/y-2) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(y^2-4)*(3/y-2) = 0

(y^2-4)*(3*y^-1-2) = 0

( 3*y^-1-2 )

3*y^-1 = 2 // : 3

y^-1 = 2/3

-1 < 0

1/(y^1) = 2/3 // * y^1

1 = 2/3*y^1 // : 2/3

3/2 = y^1

y = 3/2

( y^2-4 )

1*y^2 = 4 // : 1

y^2 = 4

y^2 = 4 // ^ 1/2

abs(y) = 2

y = 2 or y = -2

y in { 3/2, 2, -2 }

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